2x^2+44x+484=784

Solution for 2x^2+44x+484=784 equation:

2x^2+44x+484=784

We move all terms to the left:

2x^2+44x+484-(784)=0

We add all the numbers together, and all the variables

2x^2+44x-300=0

a = 2; b = 44; c = -300;
Δ = b2-4ac
Δ = 442-4·2·(-300)
Δ = 4336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4336}=\sqrt{16*271}=\sqrt{16}*\sqrt{271}=4\sqrt{271}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{271}}{2*2}=\frac{-44-4\sqrt{271}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{271}}{2*2}=\frac{-44+4\sqrt{271}}{4}
$